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Q12 - Determining Metabolic Pathway and ATP Yield from Gas Exchange in Yeast

Theoretical 2 Real exam question - full text reproduced under IBO's CC BY-NC-SA 4.0 license

Yeast can metabolize glucose using aerobic respiration (C6H12O6 + 6O2 -> 6CO2 + 6H2O, 32 ATP) and alcohol fermentation (C6H12O6 -> 2C2H5OH + 2CO2, 2 ATP) depending on environmental conditions. Yeast was cultured in a glucose solution under conditions A and B, and gas inflow and outflow from the incubator were measured: Condition A: O2 absorption 0 mL, CO2 emission 20 mL. Condition B: O2 absorption 30 mL, CO2 emission 40 mL. (Assume the same amount of glucose was completely metabolized under conditions A and B.)

Using the information and data, determine which of the statements are true or which are false.

Q12-1 Condition A. How was glucose metabolized under condition A?
Q12-1 Condition B. How was glucose metabolized under condition B?
Q12-2. Assuming that 100 equivalents of ATP were generated under condition A, how many equivalents of ATP were generated under condition B?

Question reproduced from IBO 2020, Theoretical Exam 2, licensed under CC BY-NC-SA 4.0 - attributed to the International Biology Olympiad. Open the full exam PDF · Community solutions (unofficial)