Transcription & RNA Processing
Overview
Transcription converts DNA sequence into RNA, and, in eukaryotes specifically, the resulting primary transcript is not the final functional molecule but requires a series of processing steps before export and translation. This page covers both the transcription mechanism itself and eukaryotic RNA processing, since the two are substantially co-transcriptional (processing begins before transcription of the gene even finishes) rather than strictly sequential.
Key Concepts
Prokaryotic transcription: one polymerase, direct promoter recognition
Bacteria use a single RNA polymerase for all transcription. A dissociable σ (sigma) factor subunit confers promoter-sequence specificity, directing the core polymerase to bind specific promoter consensus sequences (e.g. the −10 and −35 boxes upstream of the transcription start site), the σ factor’s role is specifically recognition and initiation; it dissociates once elongation begins, at which point the core polymerase continues alone. Different σ factors, recognising different promoter sequences, let bacteria redirect global transcription (e.g. toward stress-response genes) by simply swapping which σ factor is active, without requiring an entirely new polymerase.
Eukaryotic transcription: three specialised polymerases
Eukaryotes divide transcriptional labour across three distinct RNA polymerases, each transcribing a different class of gene:
| Polymerase | Transcribes |
|---|---|
| RNA Pol I | Most ribosomal RNA (rRNA, the major structural/catalytic RNA of ribosomes) |
| RNA Pol II | All protein-coding genes (pre-mRNA), plus most regulatory/small RNAs |
| RNA Pol III | tRNA, 5S rRNA, and other small RNAs |
RNA Pol II, the polymerase responsible for every protein-coding gene, cannot initiate transcription alone; it requires an assembly of general transcription factors (e.g. TFIID, which recognises the TATA box promoter element in many genes) to form a pre-initiation complex at the promoter before Pol II itself can begin. This is a substantially more elaborate initiation requirement than bacterial σ-factor-mediated recognition, reflecting eukaryotic transcription’s much more extensive combinatorial regulation (see Gene Regulation: Eukaryotic & Epigenetics for enhancers, the Mediator complex, and chromatin-level control layered on top of this basic initiation machinery).
Elongation and termination
Once initiated, RNA polymerase moves along the template strand 3′→5′, synthesising RNA 5′→3′ (the same fixed directionality constraint that governs DNA polymerase, see DNA Structure & Replication), using ribonucleotides rather than deoxyribonucleotides and incorporating uracil in place of thymine (see Nucleotide & Nucleic Acid Chemistry). Termination mechanisms differ between prokaryotes (a hairpin-forming terminator sequence, either intrinsic/Rho-independent or requiring the Rho protein) and eukaryotes (coupled to the polyadenylation signal, see below), the exact termination mechanism is less frequently tested at depth than the processing steps that follow.
Co-/post-transcriptional processing: three steps, three purposes
Eukaryotic pre-mRNA undergoes three distinct modifications before it is a mature, translatable mRNA: the first two begin co-transcriptionally, while Pol II is still actively transcribing the rest of the gene:
5′ capping: a modified guanine nucleotide (7-methylguanosine) is added to the 5′ end almost as soon as transcription begins, linked via an unusual 5′-5′ triphosphate bond. The cap protects the transcript from 5′ exonuclease degradation and is later recognised directly by the translation initiation machinery (see Translation & the Genetic Code).
Splicing: most eukaryotic genes contain introns (non-coding intervening sequences) interrupting the coding exons. The spliceosome, a large complex of small nuclear ribonucleoproteins (snRNPs), recognises conserved sequences at intron-exon boundaries, excises each intron as a lariat-shaped intermediate, and ligates the flanking exons together. Alternative splicing, including or excluding specific exons in different combinations, allows a single gene to produce multiple distinct protein products, a major (and often underemphasised) source of eukaryotic proteomic diversity beyond the raw number of protein-coding genes.
3′ polyadenylation: after a specific polyadenylation signal sequence is transcribed, the transcript is cleaved at that site and a long poly(A) tail (up to ~250 adenine residues) is added enzymatically, not template-directed. The poly(A) tail, like the 5′ cap, protects against degradation and is recognised by translation machinery, and its progressive shortening over the mRNA’s lifetime is one mechanism regulating mRNA stability/lifespan.
Together, the cap and poly(A) tail form a structural link (bridged by cap-binding and poly(A)-binding proteins) that effectively circularises the mature mRNA, a configuration that promotes efficient, repeated rounds of translation, covered further in Translation & the Genetic Code.
Comparative Structures
| Feature | Prokaryotic transcription | Eukaryotic transcription |
|---|---|---|
| Number of RNA polymerases | 1 | 3 (Pol I, II, III, gene-class specific) |
| Promoter recognition | σ factor (dissociable subunit of the single polymerase) | General transcription factors forming a pre-initiation complex |
| RNA processing | Minimal/none (transcript often translated as made) | Extensive: capping, splicing, polyadenylation |
| Coupling to translation | Often simultaneous (no nuclear envelope to separate the processes) | Strictly separated: transcription (nucleus) precedes translation (cytoplasm) |
| Processing step | Location added | Function |
|---|---|---|
| 5′ cap | 5′ end, co-transcriptional | Stability, translation initiation recognition |
| Splicing | Throughout transcript, co-transcriptional | Intron removal, alternative protein products |
| Poly(A) tail | 3′ end, post-cleavage | Stability, translation initiation recognition, mRNA lifespan regulation |
Common Exam Questions
- “Which RNA polymerase transcribes [gene class]?”: direct recall of the Pol I/II/III table above is a frequent, high-value memorisation target.
- “Why can prokaryotic mRNA be translated while still being transcribed, but eukaryotic mRNA cannot?”, the correct answer cites the physical separation of the nucleus (transcription) from the cytoplasm (translation) in eukaryotes, and the requirement for processing (particularly splicing) to complete before the sequence is translation-ready.
- “How does alternative splicing increase proteomic diversity beyond gene number?”: tests whether you understand that a single gene locus, through different exon-inclusion combinations, can encode functionally distinct protein isoforms, a frequently tested explanation for why proteome complexity exceeds raw gene-count estimates.
- Distinguishing the cap (5′, co-transcriptional, protects against 5′ exonucleases) from the poly(A) tail (3′, post-cleavage, protects against 3′ exonucleases and regulates lifespan) by location and timing is a common discriminator.
Visual Reference
Interactive
- A co-transcriptional processing animator: RNA Pol II moving along a gene, with the 5′ cap appearing immediately after initiation, splicing removing an intron mid-transcription, and the poly(A) tail added after cleavage at the transcript’s 3′ end.
Static
(Static images are placed inline in Key Concepts above, next to the concept each one illustrates, rather than collected here. The mature-mRNA image is a content mismatch: see the inline note; a basic mature-mRNA-structure diagram is not yet sourced.)
Practice Challenge
Competition-sourced practice questions for this topic, graded by difficulty. Click the Solution tab to reveal each answer.
Bacteriophages take control of the host transcription machinery and sequentially express different groups of phage genes. A, B, C and D are four groups of phage genes expressed in the order A, B, C, D. Each group of genes has a specific type of promoter, each of which requires a specific sigma factor to initiate transcription. The genes encoding sigma factors to transcribe group A and group D genes are located in:
A. bacterial genome and phage genome respectively.B . bacterial genome.C . phage genome.D . phage genome and bacterial genome respectively.
Which of the following is true about transcription in a bacterial cell? I. A single mRNA transcript will often code for more than one protein. II. Nascent mRNA transcripts undergo numerous post transcriptional modifications before translation initiation. III. mRNA transcripts use a start codon that codes for glycine. IV. Promoters for transcription usually feature a TATA rich region about 10bp upstream of the start codon. V. The same RNA polymerase transcribes rRNA, tRNA, and mRNA. VI. The DNA template strand is read by the polymerase in the 3’ to 5’ direction. VII. The transcript contains a purine rich sequence about 8bp before the start codon that is used in translation initiation
A. I and V only. B. I, V, VI, and VII only. C. II, III, VI, and VII only. D. II, IV, VI, and VII only. E. I, III, IV, and V only.
Bacterial core RNA Polymerase (RNAP) can bind to DNA. However, in order to initiate transcription from specific promoter sequences, it needs to associate with a sigma factor to form the holo-enzyme. Study the table below and choose the correct explanation for this phenomenon. (The numbers in the table are arbitrary.)
| Association Constant | Half life of complex (in seconds) | |||
|---|---|---|---|---|
| With non-specific DNA | With promoter DNA | With non-specific DNA | With promoter DNA | |
| Core RNAP | 1 | 1 | 1 | 1 |
| Holo RNAP | 0.001 | 100 | 0.1 | 1000 |
A. Sigma factor provides catalytic site essential for transcription.B . Holo RNAP is able to bind to a longer stretch of DNA sequence thus increasing the probability of binding to a promoter sequence.C . Binding of sigma factor increases the catalytic efficiency of core RNAP.D . Sigma factor destabilizes the non-specific RNAP-DNA complex and strengthens the RNAP-promoter complex
Practice Problems
1. A mutation disrupts the spliceosome’s ability to recognise one particular intron-exon boundary in an otherwise normal gene, but transcription itself (initiation, elongation, capping, polyadenylation) proceeds normally. Predict the most likely consequence for the resulting protein product.
Show answer
The affected intron is likely retained in the mature mRNA (or an adjacent exon is skipped, depending on exactly which boundary is disrupted), altering the reading frame or inserting/removing coding sequence in the final mRNA: this typically produces a nonfunctional, truncated, or otherwise abnormal protein, since translation (see Translation & the Genetic Code) will read straight through what should have been excised intronic sequence, very often introducing a premature stop codon downstream of the retained intron.
2. Explain why a drug that specifically inhibits RNA Pol II, without affecting Pol I or Pol III, would still severely disrupt overall cellular protein synthesis despite ribosomal RNA (rRNA) and tRNA transcription continuing normally.
3. A single gene is found to produce three structurally distinct protein isoforms in three different tissue types, despite having only one transcription start site and one promoter. Propose the most likely molecular mechanism, and name the specific processing step responsible.